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1310324215121 is a prime number
BaseRepresentation
bin10011000100010101011…
…010001100110101010001
311122021011202011220212222
4103010111122030311101
5132432020444340441
62441542111230425
7163445025026045
oct23042532146521
94567152156788
101310324215121
1146578394a889
12191b48b18415
139674201057c
14475c47c6025
15241404c6d4b
hex1311568cd51

1310324215121 has 2 divisors, whose sum is σ = 1310324215122. Its totient is φ = 1310324215120.

The previous prime is 1310324215091. The next prime is 1310324215129. The reversal of 1310324215121 is 1215124230131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 673622355025 + 636701860096 = 820745^2 + 797936^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1310324215121 is a prime.

It is not a weakly prime, because it can be changed into another prime (1310324215129) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655162107560 + 655162107561.

It is an arithmetic number, because the mean of its divisors is an integer number (655162107561).

Almost surely, 21310324215121 is an apocalyptic number.

It is an amenable number.

1310324215121 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310324215121 is an equidigital number, since it uses as much as digits as its factorization.

1310324215121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 1310324215121 its reverse (1215124230131), we get a palindrome (2525448445252).

The spelling of 1310324215121 in words is "one trillion, three hundred ten billion, three hundred twenty-four million, two hundred fifteen thousand, one hundred twenty-one".