Base | Representation |
---|---|
bin | 10011000100010101011… |
… | …010001100110101011001 |
3 | 11122021011202011220220021 |
4 | 103010111122030311121 |
5 | 132432020444341004 |
6 | 2441542111230441 |
7 | 163445025026056 |
oct | 23042532146531 |
9 | 4567152156807 |
10 | 1310324215129 |
11 | 46578394a896 |
12 | 191b48b18421 |
13 | 96742010587 |
14 | 475c47c602d |
15 | 241404c6d54 |
hex | 1311568cd59 |
1310324215129 has 2 divisors, whose sum is σ = 1310324215130. Its totient is φ = 1310324215128.
The previous prime is 1310324215121. The next prime is 1310324215141. The reversal of 1310324215129 is 9215124230131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1302513190729 + 7811024400 = 1141277^2 + 88380^2 .
It is a cyclic number.
It is not a de Polignac number, because 1310324215129 - 23 = 1310324215121 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1310324215094 and 1310324215103.
It is not a weakly prime, because it can be changed into another prime (1310324215121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655162107564 + 655162107565.
It is an arithmetic number, because the mean of its divisors is an integer number (655162107565).
Almost surely, 21310324215129 is an apocalyptic number.
It is an amenable number.
1310324215129 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310324215129 is an equidigital number, since it uses as much as digits as its factorization.
1310324215129 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12960, while the sum is 34.
The spelling of 1310324215129 in words is "one trillion, three hundred ten billion, three hundred twenty-four million, two hundred fifteen thousand, one hundred twenty-nine".
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