1310343121231 has 2 divisors, whose sum is σ = 1310343121232. Its totient is φ = 1310343121230.

The previous prime is 1310343121097. The next prime is 1310343121237. The reversal of 1310343121231 is 1321213430131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1310343121231 - 2⁹ = 1310343120719 is a prime.

It is a super-2 number, since 2×1310343121231² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1310343121196 and 1310343121205.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310343121237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655171560615 + 655171560616.

It is an arithmetic number, because the mean of its divisors is an integer number (655171560616).

Almost surely, 2^{1310343121231} is an apocalyptic number.

1310343121231 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310343121231 is an equidigital number, since it uses as much as digits as its factorization.

1310343121231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1310343121231 its reverse (1321213430131), we get a palindrome (2631556551362).

The spelling of 1310343121231 in words is "one trillion, three hundred ten billion, three hundred forty-three million, one hundred twenty-one thousand, two hundred thirty-one".