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13103441543149 is a prime number
BaseRepresentation
bin1011111010101110000111…
…1110100111111111101101
31201101200021101000101012021
42332223201332213333231
53204141322013340044
643511345443510141
72521456332250366
oct276534176477755
951350241011167
1013103441543149
1141a2158166131
121577650088351
137408594a7a09
143342d2188b6d
1517acb5ad2e84
hexbeae1fa7fed

13103441543149 has 2 divisors, whose sum is σ = 13103441543150. Its totient is φ = 13103441543148.

The previous prime is 13103441543053. The next prime is 13103441543167. The reversal of 13103441543149 is 94134514430131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7750266244900 + 5353175298249 = 2783930^2 + 2313693^2 .

It is a cyclic number.

It is not a de Polignac number, because 13103441543149 - 29 = 13103441542637 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13103448543149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551720771574 + 6551720771575.

It is an arithmetic number, because the mean of its divisors is an integer number (6551720771575).

Almost surely, 213103441543149 is an apocalyptic number.

It is an amenable number.

13103441543149 is a deficient number, since it is larger than the sum of its proper divisors (1).

13103441543149 is an equidigital number, since it uses as much as digits as its factorization.

13103441543149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 311040, while the sum is 43.

The spelling of 13103441543149 in words is "thirteen trillion, one hundred three billion, four hundred forty-one million, five hundred forty-three thousand, one hundred forty-nine".