Base | Representation |
---|---|
bin | 111101000001001110… |
… | …1010011110100101101 |
3 | 110112020020121220201222 |
4 | 1322002131103310231 |
5 | 4121331130142313 |
6 | 140110425313125 |
7 | 12316144262243 |
oct | 1720235236455 |
9 | 415206556658 |
10 | 131037740333 |
11 | 5063342a875 |
12 | 214903357a5 |
13 | c483b96b76 |
14 | 64b123c793 |
15 | 361deec208 |
hex | 1e82753d2d |
131037740333 has 4 divisors (see below), whose sum is σ = 131040419808. Its totient is φ = 131035060860.
The previous prime is 131037740261. The next prime is 131037740381. The reversal of 131037740333 is 333047730131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 131037740333 - 210 = 131037739309 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 131037740293 and 131037740302.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131037748333) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1264991 + ... + 1364652.
It is an arithmetic number, because the mean of its divisors is an integer number (32760104952).
Almost surely, 2131037740333 is an apocalyptic number.
It is an amenable number.
131037740333 is a deficient number, since it is larger than the sum of its proper divisors (2679475).
131037740333 is an equidigital number, since it uses as much as digits as its factorization.
131037740333 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2679474.
The product of its (nonzero) digits is 47628, while the sum is 35.
The spelling of 131037740333 in words is "one hundred thirty-one billion, thirty-seven million, seven hundred forty thousand, three hundred thirty-three".
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