131040003241747 has 2 divisors, whose sum is σ = 131040003241748. Its totient is φ = 131040003241746.

The previous prime is 131040003241733. The next prime is 131040003241757. The reversal of 131040003241747 is 747142300040131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131040003241747 - 2¹¹ = 131040003239699 is a prime.

It is a super-2 number, since 2×131040003241747² (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131040003241717) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65520001620873 + 65520001620874.

It is an arithmetic number, because the mean of its divisors is an integer number (65520001620874).

Almost surely, 2^{131040003241747} is an apocalyptic number.

131040003241747 is a deficient number, since it is larger than the sum of its proper divisors (1).

131040003241747 is an equidigital number, since it uses as much as digits as its factorization.

131040003241747 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 56448, while the sum is 37.

Adding to 131040003241747 its reverse (747142300040131), we get a palindrome (878182303281878).

The spelling of 131040003241747 in words is "one hundred thirty-one trillion, forty billion, three million, two hundred forty-one thousand, seven hundred forty-seven".