Base | Representation |
---|---|
bin | 11101110010111000100000… |
… | …110110000011100000010001 |
3 | 122011222022011010120221221110 |
4 | 131302320200312003200101 |
5 | 114133424411312221001 |
6 | 1142410540232443533 |
7 | 36413220303333300 |
oct | 3562704066034021 |
9 | 564868133527843 |
10 | 131040003242001 |
11 | 388318316959a7 |
12 | 1284451bb495a9 |
13 | 5817033499b09 |
14 | 24505273b8437 |
15 | 10239b7c373d6 |
hex | 772e20d83811 |
131040003242001 has 12 divisors (see below), whose sum is σ = 203245719314352. Its totient is φ = 74880001852488.
The previous prime is 131040003241951. The next prime is 131040003242003. The reversal of 131040003242001 is 100242300040131.
It is not a de Polignac number, because 131040003242001 - 215 = 131040003209233 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is not an unprimeable number, because it can be changed into a prime (131040003242003) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 445714296595 + ... + 445714296888.
It is an arithmetic number, because the mean of its divisors is an integer number (16937143276196).
Almost surely, 2131040003242001 is an apocalyptic number.
It is an amenable number.
131040003242001 is a deficient number, since it is larger than the sum of its proper divisors (72205716072351).
131040003242001 is an equidigital number, since it uses as much as digits as its factorization.
131040003242001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 891428593500 (or 891428593493 counting only the distinct ones).
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 131040003242001 its reverse (100242300040131), we get a palindrome (231282303282132).
The spelling of 131040003242001 in words is "one hundred thirty-one trillion, forty billion, three million, two hundred forty-two thousand, one".
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