Base | Representation |
---|---|
bin | 11101110010111000100000… |
… | …110110000011100000010011 |
3 | 122011222022011010120221221112 |
4 | 131302320200312003200103 |
5 | 114133424411312221003 |
6 | 1142410540232443535 |
7 | 36413220303333302 |
oct | 3562704066034023 |
9 | 564868133527845 |
10 | 131040003242003 |
11 | 388318316959a9 |
12 | 1284451bb495ab |
13 | 5817033499b0b |
14 | 24505273b8439 |
15 | 10239b7c373d8 |
hex | 772e20d83813 |
131040003242003 has 2 divisors, whose sum is σ = 131040003242004. Its totient is φ = 131040003242002.
The previous prime is 131040003241951. The next prime is 131040003242011. The reversal of 131040003242003 is 300242300040131.
It is a strong prime.
It is an emirp because it is prime and its reverse (300242300040131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131040003242003 - 28 = 131040003241747 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 131040003242003.
It is not a weakly prime, because it can be changed into another prime (131040003242053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65520001621001 + 65520001621002.
It is an arithmetic number, because the mean of its divisors is an integer number (65520001621002).
Almost surely, 2131040003242003 is an apocalyptic number.
131040003242003 is a deficient number, since it is larger than the sum of its proper divisors (1).
131040003242003 is an equidigital number, since it uses as much as digits as its factorization.
131040003242003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 131040003242003 its reverse (300242300040131), we get a palindrome (431282303282134).
The spelling of 131040003242003 in words is "one hundred thirty-one trillion, forty billion, three million, two hundred forty-two thousand, three".
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