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131040003242003 is a prime number
BaseRepresentation
bin11101110010111000100000…
…110110000011100000010011
3122011222022011010120221221112
4131302320200312003200103
5114133424411312221003
61142410540232443535
736413220303333302
oct3562704066034023
9564868133527845
10131040003242003
11388318316959a9
121284451bb495ab
135817033499b0b
1424505273b8439
1510239b7c373d8
hex772e20d83813

131040003242003 has 2 divisors, whose sum is σ = 131040003242004. Its totient is φ = 131040003242002.

The previous prime is 131040003241951. The next prime is 131040003242011. The reversal of 131040003242003 is 300242300040131.

It is a strong prime.

It is an emirp because it is prime and its reverse (300242300040131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131040003242003 - 28 = 131040003241747 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 131040003242003.

It is not a weakly prime, because it can be changed into another prime (131040003242053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65520001621001 + 65520001621002.

It is an arithmetic number, because the mean of its divisors is an integer number (65520001621002).

Almost surely, 2131040003242003 is an apocalyptic number.

131040003242003 is a deficient number, since it is larger than the sum of its proper divisors (1).

131040003242003 is an equidigital number, since it uses as much as digits as its factorization.

131040003242003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 131040003242003 its reverse (300242300040131), we get a palindrome (431282303282134).

The spelling of 131040003242003 in words is "one hundred thirty-one trillion, forty billion, three million, two hundred forty-two thousand, three".