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13104011041 = 114349273919
BaseRepresentation
bin11000011010000111…
…10101011100100001
31020211020111201210021
430031003311130201
5203314111323131
610004144233441
7642505153552
oct141503653441
936736451707
1013104011041
1156149664a0
12265860b881
13130aabb0b4
148c44c2329
1551a649e11
hex30d0f5721

13104011041 has 8 divisors (see below), whose sum is σ = 14298624000. Its totient is φ = 11909954640.

The previous prime is 13104011027. The next prime is 13104011047. The reversal of 13104011041 is 14011040131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13104011041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13104011047) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 89121 + ... + 184798.

It is an arithmetic number, because the mean of its divisors is an integer number (1787328000).

Almost surely, 213104011041 is an apocalyptic number.

13104011041 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

13104011041 is a deficient number, since it is larger than the sum of its proper divisors (1194612959).

13104011041 is a wasteful number, since it uses less digits than its factorization.

13104011041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 278279.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 13104011041 its reverse (14011040131), we get a palindrome (27115051172).

The spelling of 13104011041 in words is "thirteen billion, one hundred four million, eleven thousand, forty-one".

Divisors: 1 11 4349 47839 273919 3013109 1191273731 13104011041