Base | Representation |
---|---|
bin | 111101000001010011… |
… | …0011100010100111101 |
3 | 110112020102010112212101 |
4 | 1322002212130110331 |
5 | 4121332233300321 |
6 | 140110552505101 |
7 | 12316203523225 |
oct | 1720246342475 |
9 | 415212115771 |
10 | 131040134461 |
11 | 50634815595 |
12 | 214910ab191 |
13 | c484524802 |
14 | 64b16a3085 |
15 | 361e321791 |
hex | 1e8299c53d |
131040134461 has 2 divisors, whose sum is σ = 131040134462. Its totient is φ = 131040134460.
The previous prime is 131040134377. The next prime is 131040134471. The reversal of 131040134461 is 164431040131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 76510879236 + 54529255225 = 276606^2 + 233515^2 .
It is a cyclic number.
It is not a de Polignac number, because 131040134461 - 27 = 131040134333 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131040134471) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65520067230 + 65520067231.
It is an arithmetic number, because the mean of its divisors is an integer number (65520067231).
Almost surely, 2131040134461 is an apocalyptic number.
It is an amenable number.
131040134461 is a deficient number, since it is larger than the sum of its proper divisors (1).
131040134461 is an equidigital number, since it uses as much as digits as its factorization.
131040134461 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3456, while the sum is 28.
Adding to 131040134461 its reverse (164431040131), we get a palindrome (295471174592).
The spelling of 131040134461 in words is "one hundred thirty-one billion, forty million, one hundred thirty-four thousand, four hundred sixty-one".
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