Base | Representation |
---|---|
bin | 10011000100011010000… |
… | …000101110001011000000 |
3 | 11122021101010110102211121 |
4 | 103010122000232023000 |
5 | 132432200231001031 |
6 | 2441553510122024 |
7 | 163446653210041 |
oct | 23043200561300 |
9 | 4567333412747 |
10 | 1310401422016 |
11 | 465813493535 |
12 | 191b6a950314 |
13 | 9675500351b |
14 | 475d0b628c8 |
15 | 24147178011 |
hex | 1311a02e2c0 |
1310401422016 has 14 divisors (see below), whose sum is σ = 2600327821940. Its totient is φ = 655200710976.
The previous prime is 1310401422007. The next prime is 1310401422017. The reversal of 1310401422016 is 6102241040131.
It is not an unprimeable number, because it can be changed into a prime (1310401422017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10237511046 + ... + 10237511173.
Almost surely, 21310401422016 is an apocalyptic number.
1310401422016 is a gapful number since it is divisible by the number (16) formed by its first and last digit.
It is an amenable number.
1310401422016 is a deficient number, since it is larger than the sum of its proper divisors (1289926399924).
1310401422016 is an equidigital number, since it uses as much as digits as its factorization.
1310401422016 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20475022231 (or 20475022221 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1310401422016 its reverse (6102241040131), we get a palindrome (7412642462147).
The spelling of 1310401422016 in words is "one trillion, three hundred ten billion, four hundred one million, four hundred twenty-two thousand, sixteen".
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