13104020131 has 4 divisors (see below), whose sum is σ = 13105082032. Its totient is φ = 13102958232.

The previous prime is 13104020119. The next prime is 13104020231. The reversal of 13104020131 is 13102040131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13104020131 - 2⁵ = 13104020099 is a prime.

It is a super-2 number, since 2×13104020131² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13104020101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 512220 + ... + 537193.

It is an arithmetic number, because the mean of its divisors is an integer number (3276270508).

Almost surely, 2^13104020131 is an apocalyptic number.

13104020131 is a deficient number, since it is larger than the sum of its proper divisors (1061901).

13104020131 is a wasteful number, since it uses less digits than its factorization.

13104020131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1061900.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 13104020131 its reverse (13102040131), we get a palindrome (26206060262).

The spelling of 13104020131 in words is "thirteen billion, one hundred four million, twenty thousand, one hundred thirty-one".