Base | Representation |
---|---|
bin | 11101110010111000110010… |
… | …100110010111101000101100 |
3 | 122011222022220220002201210120 |
4 | 131302320302212113220230 |
5 | 114133431014041320134 |
6 | 1142411025553204540 |
7 | 36413230551264351 |
oct | 3562706246275054 |
9 | 564868826081716 |
10 | 131040301120044 |
11 | 388319748500a8 |
12 | 128445a3860750 |
13 | 5817080103b04 |
14 | 2450554b98628 |
15 | 10239d3e77649 |
hex | 772e32997a2c |
131040301120044 has 12 divisors (see below), whose sum is σ = 305760702613464. Its totient is φ = 43680100373344.
The previous prime is 131040301120031. The next prime is 131040301120063. The reversal of 131040301120044 is 440021103040131.
It is a tau number, because it is divible by the number of its divisors (12).
It is a junction number, because it is equal to n+sod(n) for n = 131040301119996 and 131040301120023.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5460012546657 + ... + 5460012546680.
It is an arithmetic number, because the mean of its divisors is an integer number (25480058551122).
Almost surely, 2131040301120044 is an apocalyptic number.
It is an amenable number.
131040301120044 is an abundant number, since it is smaller than the sum of its proper divisors (174720401493420).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131040301120044 is a wasteful number, since it uses less digits than its factorization.
131040301120044 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10920025093344 (or 10920025093342 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 131040301120044 its reverse (440021103040131), we get a palindrome (571061404160175).
The spelling of 131040301120044 in words is "one hundred thirty-one trillion, forty billion, three hundred one million, one hundred twenty thousand, forty-four".
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