1310403113633 has 2 divisors, whose sum is σ = 1310403113634. Its totient is φ = 1310403113632.

The previous prime is 1310403113623. The next prime is 1310403113707. The reversal of 1310403113633 is 3363113040131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1247919112609 + 62484001024 = 1117103^2 + 249968^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310403113633 - 2³⁸ = 1035525206689 is a prime.

It is a super-2 number, since 2×1310403113633² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1310403113596 and 1310403113605.

It is not a weakly prime, because it can be changed into another prime (1310403113623) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655201556816 + 655201556817.

It is an arithmetic number, because the mean of its divisors is an integer number (655201556817).

Almost surely, 2^{1310403113633} is an apocalyptic number.

It is an amenable number.

1310403113633 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310403113633 is an equidigital number, since it uses as much as digits as its factorization.

1310403113633 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5832, while the sum is 29.

Adding to 1310403113633 its reverse (3363113040131), we get a palindrome (4673516153764).

The spelling of 1310403113633 in words is "one trillion, three hundred ten billion, four hundred three million, one hundred thirteen thousand, six hundred thirty-three".