Base | Representation |
---|---|
bin | 1011111010110000010111… |
… | …0010011101100001001011 |
3 | 1201101201211020111201200202 |
4 | 2332230011302131201023 |
5 | 3204144034314144113 |
6 | 43511525224522415 |
7 | 2521510246013135 |
oct | 276540562354113 |
9 | 51351736451622 |
10 | 13104042334283 |
11 | 41a243630442a |
12 | 157779932040b |
13 | 740923abc724 |
14 | 33434bc9a055 |
15 | 17aced70a258 |
hex | beb05c9d84b |
13104042334283 has 2 divisors, whose sum is σ = 13104042334284. Its totient is φ = 13104042334282.
The previous prime is 13104042334267. The next prime is 13104042334319. The reversal of 13104042334283 is 38243324040131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13104042334283 - 24 = 13104042334267 is a prime.
It is not a weakly prime, because it can be changed into another prime (13104042334223) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552021167141 + 6552021167142.
It is an arithmetic number, because the mean of its divisors is an integer number (6552021167142).
Almost surely, 213104042334283 is an apocalyptic number.
13104042334283 is a deficient number, since it is larger than the sum of its proper divisors (1).
13104042334283 is an equidigital number, since it uses as much as digits as its factorization.
13104042334283 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 165888, while the sum is 38.
The spelling of 13104042334283 in words is "thirteen trillion, one hundred four billion, forty-two million, three hundred thirty-four thousand, two hundred eighty-three".
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