13104104034011 has 4 divisors (see below), whose sum is σ = 13104911400624. Its totient is φ = 13103296667400.

The previous prime is 13104104034001. The next prime is 13104104034013. The reversal of 13104104034011 is 11043040140131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13104104034011 - 2⁴² = 8706057522907 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13104104034013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 403658960 + ... + 403691421.

It is an arithmetic number, because the mean of its divisors is an integer number (3276227850156).

Almost surely, 2^{13104104034011} is an apocalyptic number.

13104104034011 is a deficient number, since it is larger than the sum of its proper divisors (807366613).

13104104034011 is an equidigital number, since it uses as much as digits as its factorization.

13104104034011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 807366612.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 13104104034011 its reverse (11043040140131), we get a palindrome (24147144174142).

The spelling of 13104104034011 in words is "thirteen trillion, one hundred four billion, one hundred four million, thirty-four thousand, eleven".