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131041040424221 is a prime number
BaseRepresentation
bin11101110010111001011110…
…101010100101110100011101
3122011222101211102020021110202
4131302321132222211310131
5114133434022322033341
61142411231203113245
736413255066255204
oct3562713652456435
9564871742207422
10131041040424221
11388322140a5294
121284476b372825
13581716a3250c5
1424505c504423b
151023a28d1079b
hex772e5eaa5d1d

131041040424221 has 2 divisors, whose sum is σ = 131041040424222. Its totient is φ = 131041040424220.

The previous prime is 131041040424193. The next prime is 131041040424271. The reversal of 131041040424221 is 122424040140131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 121049505062500 + 9991535361721 = 11002250^2 + 3160939^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131041040424221 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131041040424271) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65520520212110 + 65520520212111.

It is an arithmetic number, because the mean of its divisors is an integer number (65520520212111).

Almost surely, 2131041040424221 is an apocalyptic number.

It is an amenable number.

131041040424221 is a deficient number, since it is larger than the sum of its proper divisors (1).

131041040424221 is an equidigital number, since it uses as much as digits as its factorization.

131041040424221 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6144, while the sum is 29.

Adding to 131041040424221 its reverse (122424040140131), we get a palindrome (253465080564352).

The spelling of 131041040424221 in words is "one hundred thirty-one trillion, forty-one billion, forty million, four hundred twenty-four thousand, two hundred twenty-one".