Base | Representation |
---|---|
bin | 100111000011011… |
… | …0100100100100001 |
3 | 10101022202210000021 |
4 | 1032012310210201 |
5 | 10140431123131 |
6 | 334010353441 |
7 | 44321211232 |
oct | 11606644441 |
9 | 3338683007 |
10 | 1310411041 |
11 | 612769235 |
12 | 306a2b881 |
13 | 17b641964 |
14 | c6071089 |
15 | 7a099e11 |
hex | 4e1b4921 |
1310411041 has 2 divisors, whose sum is σ = 1310411042. Its totient is φ = 1310411040.
The previous prime is 1310411029. The next prime is 1310411083. The reversal of 1310411041 is 1401140131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 669308641 + 641102400 = 25871^2 + 25320^2 .
It is an emirp because it is prime and its reverse (1401140131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1310411041 - 25 = 1310411009 is a prime.
It is not a weakly prime, because it can be changed into another prime (1310411021) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655205520 + 655205521.
It is an arithmetic number, because the mean of its divisors is an integer number (655205521).
Almost surely, 21310411041 is an apocalyptic number.
It is an amenable number.
1310411041 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310411041 is an equidigital number, since it uses as much as digits as its factorization.
1310411041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 16.
The square root of 1310411041 is about 36199.6000116023. The cubic root of 1310411041 is about 1094.2986107600.
Adding to 1310411041 its reverse (1401140131), we get a palindrome (2711551172).
The spelling of 1310411041 in words is "one billion, three hundred ten million, four hundred eleven thousand, forty-one".
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