13104121111001 has 4 divisors (see below), whose sum is σ = 13104897300432. Its totient is φ = 13103344921572.

The previous prime is 13104121110973. The next prime is 13104121111019. The reversal of 13104121111001 is 10011112140131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13104121111001 - 2¹⁸ = 13104120848857 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13104121711001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 388069391 + ... + 388103156.

It is an arithmetic number, because the mean of its divisors is an integer number (3276224325108).

Almost surely, 2^{13104121111001} is an apocalyptic number.

It is an amenable number.

13104121111001 is a deficient number, since it is larger than the sum of its proper divisors (776189431).

13104121111001 is an equidigital number, since it uses as much as digits as its factorization.

13104121111001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 776189430.

The product of its (nonzero) digits is 24, while the sum is 17.

Adding to 13104121111001 its reverse (10011112140131), we get a palindrome (23115233251132).

The spelling of 13104121111001 in words is "thirteen trillion, one hundred four billion, one hundred twenty-one million, one hundred eleven thousand, one".