Base | Representation |
---|---|
bin | 10011000100011010101… |
… | …010010101101000010101 |
3 | 11122021101212222200220002 |
4 | 103010122222111220111 |
5 | 132432211024102131 |
6 | 2441554540021045 |
7 | 163450145015165 |
oct | 23043252255025 |
9 | 4567355880802 |
10 | 1310412331541 |
11 | 465819664a75 |
12 | 191b72531785 |
13 | 96757353071 |
14 | 475d23a25a5 |
15 | 241480d06cb |
hex | 1311aa95a15 |
1310412331541 has 2 divisors, whose sum is σ = 1310412331542. Its totient is φ = 1310412331540.
The previous prime is 1310412331519. The next prime is 1310412331573. The reversal of 1310412331541 is 1451332140131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1308612450916 + 1799880625 = 1143946^2 + 42425^2 .
It is a cyclic number.
It is not a de Polignac number, because 1310412331541 - 218 = 1310412069397 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1310412331141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655206165770 + 655206165771.
It is an arithmetic number, because the mean of its divisors is an integer number (655206165771).
Almost surely, 21310412331541 is an apocalyptic number.
It is an amenable number.
1310412331541 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310412331541 is an equidigital number, since it uses as much as digits as its factorization.
1310412331541 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 29.
Adding to 1310412331541 its reverse (1451332140131), we get a palindrome (2761744471672).
The spelling of 1310412331541 in words is "one trillion, three hundred ten billion, four hundred twelve million, three hundred thirty-one thousand, five hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •