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131041303132001 = 224011584977091
BaseRepresentation
bin11101110010111001101110…
…010100101111011101100001
3122011222102111201120012210112
4131302321232110233131201
5114133440042100211001
61142411313225541105
736413264436245123
oct3562715624573541
9564872451505715
10131041303132001
1138832339418559
1212844823344795
1358171ac8969b2
14245060bcab213
151023a41e04cbb
hex772e6e52f761

131041303132001 has 4 divisors (see below), whose sum is σ = 131041888333104. Its totient is φ = 131040717930900.

The previous prime is 131041303131943. The next prime is 131041303132027. The reversal of 131041303132001 is 100231303140131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131041303132001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131041303182001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 292264535 + ... + 292712556.

It is an arithmetic number, because the mean of its divisors is an integer number (32760472083276).

Almost surely, 2131041303132001 is an apocalyptic number.

It is an amenable number.

131041303132001 is a deficient number, since it is larger than the sum of its proper divisors (585201103).

131041303132001 is an equidigital number, since it uses as much as digits as its factorization.

131041303132001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 585201102.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 131041303132001 its reverse (100231303140131), we get a palindrome (231272606272132).

The spelling of 131041303132001 in words is "one hundred thirty-one trillion, forty-one billion, three hundred three million, one hundred thirty-two thousand, one".

Divisors: 1 224011 584977091 131041303132001