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13104151142355 = 32571343107695509
BaseRepresentation
bin1011111010110000110001…
…0001100001111111010011
31201101202002211020202022100
42332230030101201333103
53204144300143023410
643511544113011443
72521513036611630
oct276541421417723
951352084222270
1013104151142355
1141a2491771559
121577809853b83
137409404c83c0
1433435c501187
1517ad0804e8c0
hexbeb0c461fd3

13104151142355 has 192 divisors, whose sum is σ = 28873034910720. Its totient is φ = 5350581992448.

The previous prime is 13104151142339. The next prime is 13104151142449. The reversal of 13104151142355 is 55324115140131.

13104151142355 is a `hidden beast` number, since 1 + 3 + 1 + 0 + 415 + 1 + 1 + 4 + 235 + 5 = 666.

It is not a de Polignac number, because 13104151142355 - 24 = 13104151142339 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 18493341 + ... + 19188849.

It is an arithmetic number, because the mean of its divisors is an integer number (150380390160).

Almost surely, 213104151142355 is an apocalyptic number.

13104151142355 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

13104151142355 is an abundant number, since it is smaller than the sum of its proper divisors (15768883768365).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13104151142355 is a wasteful number, since it uses less digits than its factorization.

13104151142355 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 695690 (or 695687 counting only the distinct ones).

The product of its (nonzero) digits is 36000, while the sum is 36.

Adding to 13104151142355 its reverse (55324115140131), we get a palindrome (68428266282486).

The spelling of 13104151142355 in words is "thirteen trillion, one hundred four billion, one hundred fifty-one million, one hundred forty-two thousand, three hundred fifty-five".