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1310421211402 = 2655210605701
BaseRepresentation
bin10011000100011011001…
…100001101100100001010
311122021102111200211202211
4103010123030031210022
5132432220312231102
62441555454215334
7163450313341042
oct23043314154412
94567374624684
101310421211402
1146582367a5a6
12191b754b454a
1396759141b14
14475d3634722
1524148c867d7
hex1311b30d90a

1310421211402 has 4 divisors (see below), whose sum is σ = 1965631817106. Its totient is φ = 655210605700.

The previous prime is 1310421211391. The next prime is 1310421211403. The reversal of 1310421211402 is 2041121240131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1287228662721 + 23192548681 = 1134561^2 + 152291^2 .

It is not an unprimeable number, because it can be changed into a prime (1310421211403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 327605302849 + ... + 327605302852.

Almost surely, 21310421211402 is an apocalyptic number.

1310421211402 is a deficient number, since it is larger than the sum of its proper divisors (655210605704).

1310421211402 is an equidigital number, since it uses as much as digits as its factorization.

1310421211402 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 655210605703.

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 1310421211402 its reverse (2041121240131), we get a palindrome (3351542451533).

The spelling of 1310421211402 in words is "one trillion, three hundred ten billion, four hundred twenty-one million, two hundred eleven thousand, four hundred two".

Divisors: 1 2 655210605701 1310421211402