Base | Representation |
---|---|
bin | 111101000001010111… |
… | …0011010100110011111 |
3 | 110112020120001201220211 |
4 | 1322002232122212133 |
5 | 4121333302141133 |
6 | 140111105353251 |
7 | 12316230346606 |
oct | 1720256324637 |
9 | 415216051824 |
10 | 131042224543 |
11 | 50635a1292a |
12 | 21491938827 |
13 | c484aa6c49 |
14 | 64b1a88a3d |
15 | 361e5d5bcd |
hex | 1e82b9a99f |
131042224543 has 2 divisors, whose sum is σ = 131042224544. Its totient is φ = 131042224542.
The previous prime is 131042224517. The next prime is 131042224609. The reversal of 131042224543 is 345422240131.
It is a weak prime.
It is an emirp because it is prime and its reverse (345422240131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131042224543 - 233 = 122452289951 is a prime.
It is a super-2 number, since 2×1310422245432 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131042224043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65521112271 + 65521112272.
It is an arithmetic number, because the mean of its divisors is an integer number (65521112272).
Almost surely, 2131042224543 is an apocalyptic number.
131042224543 is a deficient number, since it is larger than the sum of its proper divisors (1).
131042224543 is an equidigital number, since it uses as much as digits as its factorization.
131042224543 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 23040, while the sum is 31.
Adding to 131042224543 its reverse (345422240131), we get a palindrome (476464464674).
The spelling of 131042224543 in words is "one hundred thirty-one billion, forty-two million, two hundred twenty-four thousand, five hundred forty-three".
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