Base | Representation |
---|---|
bin | 10011000100011011010… |
… | …000101111110001101111 |
3 | 11122021102120221020101002 |
4 | 103010123100233301233 |
5 | 132432221113300421 |
6 | 2441555535510515 |
7 | 163450326421466 |
oct | 23043320576157 |
9 | 4567376836332 |
10 | 1310422400111 |
11 | 465824311700 |
12 | 191b7598843b |
13 | 96759469bb6 |
14 | 475d38639dd |
15 | 24148e1db0b |
hex | 1311b42fc6f |
1310422400111 has 12 divisors (see below), whose sum is σ = 1440454711416. Its totient is φ = 1191232661520.
The previous prime is 1310422400101. The next prime is 1310422400113. The reversal of 1310422400111 is 1110042240131.
It is a de Polignac number, because none of the positive numbers 2k-1310422400111 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1310422400113) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2213276 + ... + 2742158.
It is an arithmetic number, because the mean of its divisors is an integer number (120037892618).
Almost surely, 21310422400111 is an apocalyptic number.
1310422400111 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
1310422400111 is a deficient number, since it is larger than the sum of its proper divisors (130032311305).
1310422400111 is a wasteful number, since it uses less digits than its factorization.
1310422400111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 549382 (or 549371 counting only the distinct ones).
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 1310422400111 its reverse (1110042240131), we get a palindrome (2420464640242).
The spelling of 1310422400111 in words is "one trillion, three hundred ten billion, four hundred twenty-two million, four hundred thousand, one hundred eleven".
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