1310424001 has 4 divisors (see below), whose sum is σ = 1342385604. Its totient is φ = 1278462400.

The previous prime is 1310423987. The next prime is 1310424007. The reversal of 1310424001 is 1004240131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1004240131 = 53 ⋅18947927.

It can be written as a sum of positive squares in 2 ways, for example, as 157753600 + 1152670401 = 12560^2 + 33951^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310424001 - 2¹¹ = 1310421953 is a prime.

It is a super-2 number, since 2×1310424001² = 3434422124793696002, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1310424007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15980740 + ... + 15980821.

It is an arithmetic number, because the mean of its divisors is an integer number (335596401).

Almost surely, 2^1310424001 is an apocalyptic number.

It is an amenable number.

1310424001 is a deficient number, since it is larger than the sum of its proper divisors (31961603).

1310424001 is an equidigital number, since it uses as much as digits as its factorization.

1310424001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31961602.

The product of its (nonzero) digits is 96, while the sum is 16.

The square root of 1310424001 is about 36199.7790186625. The cubic root of 1310424001 is about 1094.3022182956.

Adding to 1310424001 its reverse (1004240131), we get a palindrome (2314664132).

The spelling of 1310424001 in words is "one billion, three hundred ten million, four hundred twenty-four thousand, one".