1310424111433 has 2 divisors, whose sum is σ = 1310424111434. Its totient is φ = 1310424111432.

The previous prime is 1310424111421. The next prime is 1310424111473. The reversal of 1310424111433 is 3341114240131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 923853535929 + 386570575504 = 961173^2 + 621748^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1310424111433 is a prime.

It is a super-2 number, since 2×1310424111433² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1310424111473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655212055716 + 655212055717.

It is an arithmetic number, because the mean of its divisors is an integer number (655212055717).

Almost surely, 2^{1310424111433} is an apocalyptic number.

It is an amenable number.

1310424111433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310424111433 is an equidigital number, since it uses as much as digits as its factorization.

1310424111433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 1310424111433 its reverse (3341114240131), we get a palindrome (4651538351564).

The spelling of 1310424111433 in words is "one trillion, three hundred ten billion, four hundred twenty-four million, one hundred eleven thousand, four hundred thirty-three".