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1310424111473 is a prime number
BaseRepresentation
bin10011000100011011010…
…111010001100101110001
311122021102201011011220212
4103010123113101211301
5132432222033031343
62442000040313505
7163450350110051
oct23043327214561
94567381134825
101310424111473
11465825280454
12191b76472895
1396759918b39
14475d3b8b561
152414915ac18
hex1311b5d1971

1310424111473 has 2 divisors, whose sum is σ = 1310424111474. Its totient is φ = 1310424111472.

The previous prime is 1310424111433. The next prime is 1310424111509. The reversal of 1310424111473 is 3741114240131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 824304199744 + 486119911729 = 907912^2 + 697223^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310424111473 - 240 = 210912483697 is a prime.

It is a super-2 number, since 2×13104241114732 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1310424111433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655212055736 + 655212055737.

It is an arithmetic number, because the mean of its divisors is an integer number (655212055737).

Almost surely, 21310424111473 is an apocalyptic number.

It is an amenable number.

1310424111473 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310424111473 is an equidigital number, since it uses as much as digits as its factorization.

1310424111473 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8064, while the sum is 32.

The spelling of 1310424111473 in words is "one trillion, three hundred ten billion, four hundred twenty-four million, one hundred eleven thousand, four hundred seventy-three".