Search a number
-
+
1310430120000 = 2635459185089
BaseRepresentation
bin10011000100011011101…
…110001100100001000000
311122021110010110110001220
4103010123232030201000
5132432230102320000
62442000413155040
7163450452143451
oct23043356144100
94567403413056
101310430120000
11465828704781
12191b7848ba80
139675ac40991
14475d48b3128
15241499461a0
hex1311bb8c840

1310430120000 has 280 divisors, whose sum is σ = 4406045239200. Its totient is φ = 343523328000.

The previous prime is 1310430119987. The next prime is 1310430120049. The reversal of 1310430120000 is 210340131.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 6987456 + ... + 7172544.

Almost surely, 21310430120000 is an apocalyptic number.

1310430120000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1310430120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2203022619600).

1310430120000 is an abundant number, since it is smaller than the sum of its proper divisors (3095615119200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1310430120000 is an equidigital number, since it uses as much as digits as its factorization.

1310430120000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 185183 (or 185158 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 1310430120000 its reverse (210340131), we get a palindrome (1310640460131).

The spelling of 1310430120000 in words is "one trillion, three hundred ten billion, four hundred thirty million, one hundred twenty thousand".