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131043030113 = 592221068307
BaseRepresentation
bin111101000001011000…
…1011111010001100001
3110112020121120122221202
41322002301133101201
54121334003430423
6140111134530545
712316240243322
oct1720261372141
9415217518852
10131043030113
1150636413096
1221492066a55
13c484cc9808
1464b1c18449
15361e6e4728
hex1e82c5f461

131043030113 has 4 divisors (see below), whose sum is σ = 133264098480. Its totient is φ = 128821961748.

The previous prime is 131043030109. The next prime is 131043030121. The reversal of 131043030113 is 311030340131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131043030113 - 22 = 131043030109 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (131043035113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1110534095 + ... + 1110534212.

It is an arithmetic number, because the mean of its divisors is an integer number (33316024620).

Almost surely, 2131043030113 is an apocalyptic number.

It is an amenable number.

131043030113 is a deficient number, since it is larger than the sum of its proper divisors (2221068367).

131043030113 is an equidigital number, since it uses as much as digits as its factorization.

131043030113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2221068366.

The product of its (nonzero) digits is 324, while the sum is 20.

Adding to 131043030113 its reverse (311030340131), we get a palindrome (442073370244).

The spelling of 131043030113 in words is "one hundred thirty-one billion, forty-three million, thirty thousand, one hundred thirteen".

Divisors: 1 59 2221068307 131043030113