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1310430304153 is a prime number
BaseRepresentation
bin10011000100011011101…
…110111001011110011001
311122021110010210210200101
4103010123232321132121
5132432230124213103
62442000421135401
7163450453541365
oct23043356713631
94567403723611
101310430304153
11465828820073
12191b7855a561
139675aca6749
14475d49202a5
1524149980a1d
hex1311bbb9799

1310430304153 has 2 divisors, whose sum is σ = 1310430304154. Its totient is φ = 1310430304152.

The previous prime is 1310430304067. The next prime is 1310430304159. The reversal of 1310430304153 is 3514030340131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 859240010304 + 451190293849 = 926952^2 + 671707^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310430304153 - 29 = 1310430303641 is a prime.

It is not a weakly prime, because it can be changed into another prime (1310430304159) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655215152076 + 655215152077.

It is an arithmetic number, because the mean of its divisors is an integer number (655215152077).

Almost surely, 21310430304153 is an apocalyptic number.

It is an amenable number.

1310430304153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310430304153 is an equidigital number, since it uses as much as digits as its factorization.

1310430304153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6480, while the sum is 28.

Adding to 1310430304153 its reverse (3514030340131), we get a palindrome (4824460644284).

The spelling of 1310430304153 in words is "one trillion, three hundred ten billion, four hundred thirty million, three hundred four thousand, one hundred fifty-three".