131043040000000 has 384 divisors, whose sum is σ = 328542928459200. Its totient is φ = 52254720000000.

The previous prime is 131043039999961. The next prime is 131043040000009. The reversal of 131043040000000 is 40340131.

It is a Harshad number since it is a multiple of its sum of digits (16).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131043040000009) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 60639998920 + ... + 60640001080.

Almost surely, 2^{131043040000000} is an apocalyptic number.

131043040000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131043040000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (164271464229600).

131043040000000 is an abundant number, since it is smaller than the sum of its proper divisors (197499888459200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131043040000000 is an frugal number, since it uses more digits than its factorization.

131043040000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2597 (or 2547 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 16.

Adding to 131043040000000 its reverse (40340131), we get a palindrome (131043080340131).

The spelling of 131043040000000 in words is "one hundred thirty-one trillion, forty-three billion, forty million", and thus it is an aban number.