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13104320213 = 21162105783
BaseRepresentation
bin11000011010001010…
…00000111011010101
31020211021002102220002
430031011000323111
5203314201221323
610004155021045
7642510612125
oct141505007325
936737072802
1013104320213
115615057806
12265873a785
13130ab98a3a
148c4562c85
1551a6ab828
hex30d140ed5

13104320213 has 4 divisors (see below), whose sum is σ = 13166426208. Its totient is φ = 13042214220.

The previous prime is 13104320191. The next prime is 13104320221. The reversal of 13104320213 is 31202340131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13104320213 - 28 = 13104319957 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13104320813) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31052681 + ... + 31053102.

It is an arithmetic number, because the mean of its divisors is an integer number (3291606552).

Almost surely, 213104320213 is an apocalyptic number.

It is an amenable number.

13104320213 is a deficient number, since it is larger than the sum of its proper divisors (62105995).

13104320213 is an equidigital number, since it uses as much as digits as its factorization.

13104320213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 62105994.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 13104320213 its reverse (31202340131), we get a palindrome (44306660344).

The spelling of 13104320213 in words is "thirteen billion, one hundred four million, three hundred twenty thousand, two hundred thirteen".

Divisors: 1 211 62105783 13104320213