Base | Representation |
---|---|
bin | 1011111010110001011001… |
… | …0110100000101111110101 |
3 | 1201101202112121101210102212 |
4 | 2332230112112200233311 |
5 | 3204200121434021044 |
6 | 43512012552543205 |
7 | 2521520162010044 |
oct | 276542626405765 |
9 | 51352477353385 |
10 | 13104320220149 |
11 | 41a2569154174 |
12 | 15778563b1b05 |
13 | 740969546a32 |
14 | 334376b5455b |
15 | 17ad17ceba9e |
hex | beb165a0bf5 |
13104320220149 has 2 divisors, whose sum is σ = 13104320220150. Its totient is φ = 13104320220148.
The previous prime is 13104320220091. The next prime is 13104320220203. The reversal of 13104320220149 is 94102202340131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11711110622500 + 1393209597649 = 3422150^2 + 1180343^2 .
It is a cyclic number.
It is not a de Polignac number, because 13104320220149 - 228 = 13104051784693 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13104320223149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552160110074 + 6552160110075.
It is an arithmetic number, because the mean of its divisors is an integer number (6552160110075).
Almost surely, 213104320220149 is an apocalyptic number.
It is an amenable number.
13104320220149 is a deficient number, since it is larger than the sum of its proper divisors (1).
13104320220149 is an equidigital number, since it uses as much as digits as its factorization.
13104320220149 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10368, while the sum is 32.
The spelling of 13104320220149 in words is "thirteen trillion, one hundred four billion, three hundred twenty million, two hundred twenty thousand, one hundred forty-nine".
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