Base | Representation |
---|---|
bin | 10011000100011011110… |
… | …101100000000100110111 |
3 | 11122021110021001202010112 |
4 | 103010123311200010313 |
5 | 132432231100111002 |
6 | 2442000522213235 |
7 | 163450504341065 |
oct | 23043365400467 |
9 | 4567407052115 |
10 | 1310432035127 |
11 | 4658297a2626 |
12 | 191b7905421b |
13 | 9675b4615a7 |
14 | 475d4c51035 |
15 | 24149bc3852 |
hex | 1311bd60137 |
1310432035127 has 2 divisors, whose sum is σ = 1310432035128. Its totient is φ = 1310432035126.
The previous prime is 1310432035043. The next prime is 1310432035151. The reversal of 1310432035127 is 7215302340131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1310432035127 - 226 = 1310364926263 is a prime.
It is a super-2 number, since 2×13104320351272 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1310432035093 and 1310432035102.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1310432035427) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655216017563 + 655216017564.
It is an arithmetic number, because the mean of its divisors is an integer number (655216017564).
Almost surely, 21310432035127 is an apocalyptic number.
1310432035127 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310432035127 is an equidigital number, since it uses as much as digits as its factorization.
1310432035127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15120, while the sum is 32.
Adding to 1310432035127 its reverse (7215302340131), we get a palindrome (8525734375258).
The spelling of 1310432035127 in words is "one trillion, three hundred ten billion, four hundred thirty-two million, thirty-five thousand, one hundred twenty-seven".
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