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1310432121197 is a prime number
BaseRepresentation
bin10011000100011011110…
…101110101000101101101
311122021110021020010012022
4103010123311311011231
5132432231110334242
62442000524115525
7163450505150033
oct23043365650555
94567407203168
101310432121197
11465829851261
12191b79095ba5
139675b491814
14475d4c74553
1524149bde0d2
hex1311bd7516d

1310432121197 has 2 divisors, whose sum is σ = 1310432121198. Its totient is φ = 1310432121196.

The previous prime is 1310432121161. The next prime is 1310432121203. The reversal of 1310432121197 is 7911212340131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 979359619876 + 331072501321 = 989626^2 + 575389^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310432121197 - 28 = 1310432120941 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310432121137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655216060598 + 655216060599.

It is an arithmetic number, because the mean of its divisors is an integer number (655216060599).

Almost surely, 21310432121197 is an apocalyptic number.

It is an amenable number.

1310432121197 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310432121197 is an equidigital number, since it uses as much as digits as its factorization.

1310432121197 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9072, while the sum is 35.

The spelling of 1310432121197 in words is "one trillion, three hundred ten billion, four hundred thirty-two million, one hundred twenty-one thousand, one hundred ninety-seven".