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1310432479357 is a prime number
BaseRepresentation
bin10011000100011011110…
…111001100100001111101
311122021110021220022111111
4103010123313030201331
5132432231203314412
62442000535522021
7163450511201161
oct23043367144175
94567407808444
101310432479357
11465829a76361
12191b79229311
139675b588851
14475d4d28ca1
1524149c602a7
hex1311bdcc87d

1310432479357 has 2 divisors, whose sum is σ = 1310432479358. Its totient is φ = 1310432479356.

The previous prime is 1310432479327. The next prime is 1310432479397. The reversal of 1310432479357 is 7539742340131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 769022009721 + 541410469636 = 876939^2 + 735806^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1310432479357 is a prime.

It is a super-2 number, since 2×13104324793572 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1310432479357.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310432479327) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655216239678 + 655216239679.

It is an arithmetic number, because the mean of its divisors is an integer number (655216239679).

Almost surely, 21310432479357 is an apocalyptic number.

It is an amenable number.

1310432479357 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310432479357 is an equidigital number, since it uses as much as digits as its factorization.

1310432479357 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1905120, while the sum is 49.

The spelling of 1310432479357 in words is "one trillion, three hundred ten billion, four hundred thirty-two million, four hundred seventy-nine thousand, three hundred fifty-seven".