Base | Representation |
---|---|
bin | 10011000100011011110… |
… | …111010101000101111111 |
3 | 11122021110021222002121112 |
4 | 103010123313111011333 |
5 | 132432231210430211 |
6 | 2442000540352235 |
7 | 163450511405345 |
oct | 23043367250577 |
9 | 4567407862545 |
10 | 1310432514431 |
11 | 465829a9a747 |
12 | 191b7924567b |
13 | 9675b59b7c1 |
14 | 475d4d37995 |
15 | 24149c6a88b |
hex | 1311bdd517f |
1310432514431 has 2 divisors, whose sum is σ = 1310432514432. Its totient is φ = 1310432514430.
The previous prime is 1310432514409. The next prime is 1310432514481. The reversal of 1310432514431 is 1344152340131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1310432514431 is a prime.
It is a super-2 number, since 2×13104325144312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1310432514481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655216257215 + 655216257216.
It is an arithmetic number, because the mean of its divisors is an integer number (655216257216).
Almost surely, 21310432514431 is an apocalyptic number.
1310432514431 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310432514431 is an equidigital number, since it uses as much as digits as its factorization.
1310432514431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 32.
Adding to 1310432514431 its reverse (1344152340131), we get a palindrome (2654584854562).
The spelling of 1310432514431 in words is "one trillion, three hundred ten billion, four hundred thirty-two million, five hundred fourteen thousand, four hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •