Base | Representation |
---|---|
bin | 1011111010110001011010… |
… | …1010101101010011010111 |
3 | 1201101202112222100202212021 |
4 | 2332230112222231103113 |
5 | 3204200124312430310 |
6 | 43512013302234011 |
7 | 2521520255010250 |
oct | 276542652552327 |
9 | 51352488322767 |
10 | 13104325514455 |
11 | 41a257113a92a |
12 | 1577858125907 |
13 | 74096a67b766 |
14 | 334377731b27 |
15 | 17ad184e55da |
hex | beb16aad4d7 |
13104325514455 has 16 divisors (see below), whose sum is σ = 17995965327360. Its totient is φ = 8973663756192.
The previous prime is 13104325514443. The next prime is 13104325514461. The reversal of 13104325514455 is 55441552340131.
It is a cyclic number.
It is not a de Polignac number, because 13104325514455 - 211 = 13104325512407 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 253295719 + ... + 253347448.
It is an arithmetic number, because the mean of its divisors is an integer number (1124747832960).
Almost surely, 213104325514455 is an apocalyptic number.
13104325514455 is a deficient number, since it is larger than the sum of its proper divisors (4891639812905).
13104325514455 is an equidigital number, since it uses as much as digits as its factorization.
13104325514455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 506643918.
The product of its (nonzero) digits is 720000, while the sum is 43.
Adding to 13104325514455 its reverse (55441552340131), we get a palindrome (68545877854586).
The spelling of 13104325514455 in words is "thirteen trillion, one hundred four billion, three hundred twenty-five million, five hundred fourteen thousand, four hundred fifty-five".
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