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13104325515245 = 591927111051961
BaseRepresentation
bin1011111010110001011010…
…1010101101011111101101
31201101202112222100210221112
42332230112222231133231
53204200124312441440
643512013302241405
72521520255012456
oct276542652553755
951352488323845
1013104325515245
1141a2571140488
121577858126265
1374096a67bc23
1433437773212d
1517ad184e5965
hexbeb16aad7ed

13104325515245 has 16 divisors (see below), whose sum is σ = 15748123610880. Its totient is φ = 10468180195200.

The previous prime is 13104325515191. The next prime is 13104325515287. The reversal of 13104325515245 is 54251552340131.

It is not a de Polignac number, because 13104325515245 - 224 = 13104308738029 is a prime.

It is a super-2 number, since 2×131043255152452 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11931065 + ... + 12983025.

It is an arithmetic number, because the mean of its divisors is an integer number (984257725680).

Almost surely, 213104325515245 is an apocalyptic number.

It is an amenable number.

13104325515245 is a deficient number, since it is larger than the sum of its proper divisors (2643798095635).

13104325515245 is a wasteful number, since it uses less digits than its factorization.

13104325515245 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1055596.

The product of its (nonzero) digits is 360000, while the sum is 41.

Adding to 13104325515245 its reverse (54251552340131), we get a palindrome (67355877855376).

The spelling of 13104325515245 in words is "thirteen trillion, one hundred four billion, three hundred twenty-five million, five hundred fifteen thousand, two hundred forty-five".

Divisors: 1 5 919 2711 4595 13555 1051961 2491409 5259805 12457045 966752159 2851866271 4833760795 14259331355 2620865103049 13104325515245