13104331249843 has 2 divisors, whose sum is σ = 13104331249844. Its totient is φ = 13104331249842.

The previous prime is 13104331249837. The next prime is 13104331249861. The reversal of 13104331249843 is 34894213340131.

It is a happy number.

13104331249843 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13104331249843 - 2¹⁷ = 13104331118771 is a prime.

It is a super-2 number, since 2×13104331249843² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13104331249793 and 13104331249802.

It is not a weakly prime, because it can be changed into another prime (13104331240843) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552165624921 + 6552165624922.

It is an arithmetic number, because the mean of its divisors is an integer number (6552165624922).

Almost surely, 2^{13104331249843} is an apocalyptic number.

13104331249843 is a deficient number, since it is larger than the sum of its proper divisors (1).

13104331249843 is an equidigital number, since it uses as much as digits as its factorization.

13104331249843 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 746496, while the sum is 46.

Adding to 13104331249843 its reverse (34894213340131), we get a palindrome (47998544589974).

The spelling of 13104331249843 in words is "thirteen trillion, one hundred four billion, three hundred thirty-one million, two hundred forty-nine thousand, eight hundred forty-three".