13104331307161 has 2 divisors, whose sum is σ = 13104331307162. Its totient is φ = 13104331307160.

The previous prime is 13104331307143. The next prime is 13104331307213. The reversal of 13104331307161 is 16170313340131.

13104331307161 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12234737756761 + 869593550400 = 3497819^2 + 932520^2 .

It is an emirp because it is prime and its reverse (16170313340131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13104331307161 - 2⁵ = 13104331307129 is a prime.

It is not a weakly prime, because it can be changed into another prime (13104331307101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552165653580 + 6552165653581.

It is an arithmetic number, because the mean of its divisors is an integer number (6552165653581).

Almost surely, 2^{13104331307161} is an apocalyptic number.

It is an amenable number.

13104331307161 is a deficient number, since it is larger than the sum of its proper divisors (1).

13104331307161 is an equidigital number, since it uses as much as digits as its factorization.

13104331307161 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13608, while the sum is 34.

Adding to 13104331307161 its reverse (16170313340131), we get a palindrome (29274644647292).

The spelling of 13104331307161 in words is "thirteen trillion, one hundred four billion, three hundred thirty-one million, three hundred seven thousand, one hundred sixty-one".