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13104331307143 is a prime number
BaseRepresentation
bin1011111010110001011100…
…0000110011100010000111
31201101202120101021001221021
42332230113000303202013
53204200132303312033
643512014030332011
72521520355154456
oct276542700634207
951352511231837
1013104331307143
1141a2574436a7a
12157785a05a007
1374096b92929b
143343783dcb9d
1517ad18c8bb2d
hexbeb17033887

13104331307143 has 2 divisors, whose sum is σ = 13104331307144. Its totient is φ = 13104331307142.

The previous prime is 13104331307129. The next prime is 13104331307161. The reversal of 13104331307143 is 34170313340131.

It is a happy number.

13104331307143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13104331307143 - 241 = 10905308051591 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13104331307099 and 13104331307108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13104331347143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552165653571 + 6552165653572.

It is an arithmetic number, because the mean of its divisors is an integer number (6552165653572).

Almost surely, 213104331307143 is an apocalyptic number.

13104331307143 is a deficient number, since it is larger than the sum of its proper divisors (1).

13104331307143 is an equidigital number, since it uses as much as digits as its factorization.

13104331307143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27216, while the sum is 34.

Adding to 13104331307143 its reverse (34170313340131), we get a palindrome (47274644647274).

The spelling of 13104331307143 in words is "thirteen trillion, one hundred four billion, three hundred thirty-one million, three hundred seven thousand, one hundred forty-three".