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13104331313239 is a prime number
BaseRepresentation
bin1011111010110001011100…
…0000110101000001010111
31201101202120101021101022001
42332230113000311001113
53204200132304010424
643512014030420131
72521520355211315
oct276542700650127
951352511241261
1013104331313239
1141a2574440611
12157785a061647
1374096b92bcaa
143343784010b5
1517ad18c8d844
hexbeb17035057

13104331313239 has 2 divisors, whose sum is σ = 13104331313240. Its totient is φ = 13104331313238.

The previous prime is 13104331313221. The next prime is 13104331313243. The reversal of 13104331313239 is 93231313340131.

13104331313239 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13104331313239 - 27 = 13104331313111 is a prime.

It is a super-2 number, since 2×131043313132392 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13104331313198 and 13104331313207.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13104331313299) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552165656619 + 6552165656620.

It is an arithmetic number, because the mean of its divisors is an integer number (6552165656620).

Almost surely, 213104331313239 is an apocalyptic number.

13104331313239 is a deficient number, since it is larger than the sum of its proper divisors (1).

13104331313239 is an equidigital number, since it uses as much as digits as its factorization.

13104331313239 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 52488, while the sum is 37.

The spelling of 13104331313239 in words is "thirteen trillion, one hundred four billion, three hundred thirty-one million, three hundred thirteen thousand, two hundred thirty-nine".