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BaseRepresentation
bin1011111010110001011100…
…0000110101100010010101
31201101202120101021111012012
42332230113000311202111
53204200132304042344
643512014030434005
72521520355220421
oct276542700654225
951352511244165
1013104331315349
1141a257444215a
12157785a062905
1374096b92cc41
14334378401b81
hexbeb17035895

13104331315349 has 2 divisors, whose sum is σ = 13104331315350. Its totient is φ = 13104331315348.

The previous prime is 13104331315321. The next prime is 13104331315379. The reversal of 13104331315349 is 94351313340131.

13104331315349 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11950973452324 + 1153357863025 = 3457018^2 + 1073945^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13104331315349 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13104331315379) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552165657674 + 6552165657675.

It is an arithmetic number, because the mean of its divisors is an integer number (6552165657675).

Almost surely, 213104331315349 is an apocalyptic number.

It is an amenable number.

13104331315349 is a deficient number, since it is larger than the sum of its proper divisors (1).

13104331315349 is an equidigital number, since it uses as much as digits as its factorization.

13104331315349 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 174960, while the sum is 41.

The spelling of 13104331315349 in words is "thirteen trillion, one hundred four billion, three hundred thirty-one million, three hundred fifteen thousand, three hundred forty-nine".