13104331315841 has 2 divisors, whose sum is σ = 13104331315842. Its totient is φ = 13104331315840.

The previous prime is 13104331315769. The next prime is 13104331315849. The reversal of 13104331315841 is 14851313340131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11683715241025 + 1420616074816 = 3418145^2 + 1191896^2 .

It is an emirp because it is prime and its reverse (14851313340131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13104331315841 - 2¹⁰ = 13104331314817 is a prime.

It is a super-2 number, since 2×13104331315841² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13104331315795 and 13104331315804.

It is not a weakly prime, because it can be changed into another prime (13104331315849) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552165657920 + 6552165657921.

It is an arithmetic number, because the mean of its divisors is an integer number (6552165657921).

Almost surely, 2^{13104331315841} is an apocalyptic number.

It is an amenable number.

13104331315841 is a deficient number, since it is larger than the sum of its proper divisors (1).

13104331315841 is an equidigital number, since it uses as much as digits as its factorization.

13104331315841 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 51840, while the sum is 38.

Adding to 13104331315841 its reverse (14851313340131), we get a palindrome (27955644655972).

The spelling of 13104331315841 in words is "thirteen trillion, one hundred four billion, three hundred thirty-one million, three hundred fifteen thousand, eight hundred forty-one".