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13104331315849 is a prime number
BaseRepresentation
bin1011111010110001011100…
…0000110101101010001001
31201101202120101021111212201
42332230113000311222021
53204200132304101344
643512014030440201
72521520355222034
oct276542700655211
951352511244781
1013104331315849
1141a2574442574
12157785a063061
1374096b930237
1433437840201b
1517ad18c8e4d4
hexbeb17035a89

13104331315849 has 2 divisors, whose sum is σ = 13104331315850. Its totient is φ = 13104331315848.

The previous prime is 13104331315841. The next prime is 13104331315891. The reversal of 13104331315849 is 94851313340131.

13104331315849 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11402237958400 + 1702093357449 = 3376720^2 + 1304643^2 .

It is a cyclic number.

It is not a de Polignac number, because 13104331315849 - 23 = 13104331315841 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13104331315799 and 13104331315808.

It is not a weakly prime, because it can be changed into another prime (13104331315841) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552165657924 + 6552165657925.

It is an arithmetic number, because the mean of its divisors is an integer number (6552165657925).

Almost surely, 213104331315849 is an apocalyptic number.

It is an amenable number.

13104331315849 is a deficient number, since it is larger than the sum of its proper divisors (1).

13104331315849 is an equidigital number, since it uses as much as digits as its factorization.

13104331315849 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 466560, while the sum is 46.

The spelling of 13104331315849 in words is "thirteen trillion, one hundred four billion, three hundred thirty-one million, three hundred fifteen thousand, eight hundred forty-nine".