Base | Representation |
---|---|
bin | 1011111010110001011100… |
… | …0000111101010011000111 |
3 | 1201101202120101100002210202 |
4 | 2332230113000331103013 |
5 | 3204200132311102033 |
6 | 43512014031241115 |
7 | 2521520355412211 |
oct | 276542700752307 |
9 | 51352511302722 |
10 | 13104331347143 |
11 | 41a2574464033 |
12 | 157785a07919b |
13 | 74096b94155a |
14 | 33437840d5b1 |
15 | 17ad18c988e8 |
hex | beb1703d4c7 |
13104331347143 has 2 divisors, whose sum is σ = 13104331347144. Its totient is φ = 13104331347142.
The previous prime is 13104331347139. The next prime is 13104331347179. The reversal of 13104331347143 is 34174313340131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13104331347143 - 22 = 13104331347139 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13104331347097 and 13104331347106.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13104331347193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552165673571 + 6552165673572.
It is an arithmetic number, because the mean of its divisors is an integer number (6552165673572).
Almost surely, 213104331347143 is an apocalyptic number.
13104331347143 is a deficient number, since it is larger than the sum of its proper divisors (1).
13104331347143 is an equidigital number, since it uses as much as digits as its factorization.
13104331347143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108864, while the sum is 38.
Adding to 13104331347143 its reverse (34174313340131), we get a palindrome (47278644687274).
The spelling of 13104331347143 in words is "thirteen trillion, one hundred four billion, three hundred thirty-one million, three hundred forty-seven thousand, one hundred forty-three".
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