Base | Representation |
---|---|
bin | 11101110010111011100111… |
… | …010000110000010110111011 |
3 | 122011222121202010111000010021 |
4 | 131302323213100300112323 |
5 | 114134003221011131420 |
6 | 1142412250430231311 |
7 | 36413365634403640 |
oct | 3562734720602673 |
9 | 564877663430107 |
10 | 131043332130235 |
11 | 3883318a7709a8 |
12 | 128450aa955537 |
13 | 5817444055075 |
14 | 2450761553dc7 |
15 | 1023b100e47aa |
hex | 772ee74305bb |
131043332130235 has 16 divisors (see below), whose sum is σ = 179719359652800. Its totient is φ = 89856889952256.
The previous prime is 131043332130223. The next prime is 131043332130247. The reversal of 131043332130235 is 532031233340131.
It is an interprime number because it is at equal distance from previous prime (131043332130223) and next prime (131043332130247).
It is a de Polignac number, because none of the positive numbers 2k-131043332130235 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 131043332130235.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 26771830 + ... + 31286059.
It is an arithmetic number, because the mean of its divisors is an integer number (11232459978300).
Almost surely, 2131043332130235 is an apocalyptic number.
131043332130235 is a deficient number, since it is larger than the sum of its proper divisors (48676027522565).
131043332130235 is an equidigital number, since it uses as much as digits as its factorization.
131043332130235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 58122390.
The product of its (nonzero) digits is 58320, while the sum is 34.
Adding to 131043332130235 its reverse (532031233340131), we get a palindrome (663074565470366).
The spelling of 131043332130235 in words is "one hundred thirty-one trillion, forty-three billion, three hundred thirty-two million, one hundred thirty thousand, two hundred thirty-five".
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