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131043332131213 is a prime number
BaseRepresentation
bin11101110010111011100111…
…010000110000100110001101
3122011222121202010111001110111
4131302323213100300212031
5114134003221011144323
61142412250430240021
736413365634406535
oct3562734720604615
9564877663431414
10131043332131213
113883318a771707
12128450aa956011
135817444055648
1424507615544c5
151023b100e4c0d
hex772ee743098d

131043332131213 has 2 divisors, whose sum is σ = 131043332131214. Its totient is φ = 131043332131212.

The previous prime is 131043332131169. The next prime is 131043332131259. The reversal of 131043332131213 is 312131233340131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 111078994517604 + 19964337613609 = 10539402^2 + 4468147^2 .

It is a cyclic number.

It is not a de Polignac number, because 131043332131213 - 221 = 131043330034061 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131043332431213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65521666065606 + 65521666065607.

It is an arithmetic number, because the mean of its divisors is an integer number (65521666065607).

Almost surely, 2131043332131213 is an apocalyptic number.

It is an amenable number.

131043332131213 is a deficient number, since it is larger than the sum of its proper divisors (1).

131043332131213 is an equidigital number, since it uses as much as digits as its factorization.

131043332131213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11664, while the sum is 31.

Adding to 131043332131213 its reverse (312131233340131), we get a palindrome (443174565471344).

The spelling of 131043332131213 in words is "one hundred thirty-one trillion, forty-three billion, three hundred thirty-two million, one hundred thirty-one thousand, two hundred thirteen".